how to solve this word problem
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according to question :-
LP bisect the triangle LMN
and it is also given that angle MPL and angle LPN is 90 degrees
so angle MPL and angle LPN are equal
and PN = PM (given)
and LP = LP
so if PN = PM
angle MPL = angle LPN
and LP=LP
so by SAS (Side angle side) it is proved that the triangle LPM is congruent to triangle LPN
therefore by CPCT :-
LM = LN
and though LM = LN therefore the triangle LMN is isosceles
and since MP = PN therefore angle MLP = angle NLP
and since LP = LP therefore Angle M = angle N
now according to question all is proved
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