Question

How to solve this x²-6x+8 by factorisation method?

Answer 1

${x}^{2} - 6x + 8 = 0$
can be written as,


${x}^{2} - 4x - 2x + 8 = 0$
taking x common in first two terms and -2 in the last two.

$x(x - 4) - 2(x - 4) = 0$
taking x-4 common

$(x - 4)(x - 2) = 0$

either x-4 =0 or x-2 =0

therefore,


x=2 or x=4.




Hope this helps.

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Answer 2

Hello,

x^2 -6x +8

x^2-4x-2x+8

x(x-4)-2(x-4)

(x-2)(x-4)



that's all