How to solve water jug problem in AI?
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Water jug problem in Artificial Intelligence
(x,y) If x<4. (4,y) Fill the 4 gallon jug completely.
(x,y) if y<3. (x,3) Fill the 3 gallon jug completely.
(x,y) If x>0. (x-d,y) Pour some part from the 4 gallon jug.
(x,y) If y>0. (x,y-d) Pour some part from the 3 gallon jug.
(x,y) If x>0. (0,y) ...
(x,y) If y>0. (x,0) ...
(x,y) If (x+y)<7. (4, y-[4-x]) ...
(x,y) If (x+y)<7. (x-[3-y],y)
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int main() {
int side, area;
printf("\nEnter the Length of Side : ");
scanf("%d", &side);
area = side * side;
printf("\nArea of Square : %d", area);
return (0);
int side, area;
printf("\nEnter the Length of Side : ");
scanf("%d", &side);
area = side * side;
printf("\nArea of Square : %d", area);
return (0);
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