how to solve x^2+10x-1200
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x^2 ,+ 10x + 25 - 1225
(X+ 5)^2 - 35^2
(X + 40)(x- 30)
Answered by
3
hey mate
here is ur answer
x²+10x-1200
x²- 30x+ 40x-1200 (by splitting middle term)
X(X+30) + 40(x-30). (30*40=1200, 40-30=10)
(x-30)(X+40)
so roots of this equation :
x-30=0. .x+40=0
X=30. X= -40
X = 30 or -40
hope it helps u
pleasure to help you
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