Math, asked by kavangcb, 11 months ago

how to solve x^2+10x-1200​

Answers

Answered by Anonymous
0

x^2 ,+ 10x + 25 - 1225

(X+ 5)^2 - 35^2

(X + 40)(x- 30)

Answered by Anonymous
3

hey mate

here is ur answer

x²+10x-1200

x²- 30x+ 40x-1200 (by splitting middle term)

X(X+30) + 40(x-30). (30*40=1200, 40-30=10)

(x-30)(X+40)

so roots of this equation :

x-30=0. .x+40=0

X=30. X= -40

X = 30 or -40

hope it helps u

pleasure to help you

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