Math, asked by shahanshahalam, 1 year ago

how to solve X^2-(x-2)^2=32

Answers

Answered by Melantha
3

x^2 - (x - 2)^2 - 32 = 0

x^2 - (x^2 - 4 x + 4) - 32 = 0

x^2 - x^2 + 4 x - 4 - 32 = 0

4 x - 4 - 32 = 0

4 x - 36 = 0

4 x = 36

x = 9


shahanshahalam: thanks sir
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shahanshahalam: mam how to solve(x+4)^2-(x-5)^2=9
Answered by aichrajrup
0

x^2 - ( x^2 - 2ab + 2^ 2) = 32

x^2 -x^2+2ab-4 =32

2ab=32+4

ab=36/2

ab=18


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