how to solve (x+2y)square
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(x+2y)^2
=(x)^2 + 2×x×2y + (2y)^2
= x^2+4xy+4y^2
=(x)^2 + 2×x×2y + (2y)^2
= x^2+4xy+4y^2
jaxx:
it is wrong ans
how
i am sure its correct
there are many ways to find out the problem in maths so in that this is one of the way to do
your answer is wrong
you didnt square 2y
it becomes 4y^2
Answered by
2
this is the answer I hope
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