How to solve x^5-13x^3+36x=
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Take x=2
then check if P(x)=0
ieP(2)=0
(2)^5-13 (2)³+ 36 (2)=0
32-104+72=0
104-104=0
therefore x=2 is a zero of the polynomial
then check if P(x)=0
ieP(2)=0
(2)^5-13 (2)³+ 36 (2)=0
32-104+72=0
104-104=0
therefore x=2 is a zero of the polynomial
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