how to solve x square-5x-36
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Answered by
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x^2-5x-36=0
x^2-9x+4x-36=0
x(x-9)+4(x-9)=0
(x+4)(x-9)=0
x=-4 x=9
x^2-9x+4x-36=0
x(x-9)+4(x-9)=0
(x+4)(x-9)=0
x=-4 x=9
Answered by
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it is a question from quadratic equationa.and there will be two values of x.
Solution:
x square-5x-36=0
x square+4x-5x-36=0 (4x-9x=-5x)
x(x+4)-9(x+4)=0
(x-9)(x+4)=0
x=9,x=-4
Solution:
x square-5x-36=0
x square+4x-5x-36=0 (4x-9x=-5x)
x(x+4)-9(x+4)=0
(x-9)(x+4)=0
x=9,x=-4
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