how to solve x+y=0 x-y=2 by substitution method
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Solve equation [2] for the variable x
[2] x = y + 2
// Plug this in for variable x in equation [1]
[1] (y +2) + y = 0
[1] 2y = -2
// Solve equation [1] for the variable y
[1] 2y = - 2
[1] y = - 1
// By now we know this much :
x = y+2
y = -1
// Use the y value to solve for x
x = (-1)+2 = 1
Solution :
{x,y} = {1,-1}
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