How to solve {x+y+z} {x-y-z} ?
Answers
Answered by
0
{x+y+z}{x-(y+z)}.
reason because
(a-b)(a+b)=a^2-b^2
so. {x^2-(y+z)^2}
=x^2-y^2-z^2-2yz
reason because
(a-b)(a+b)=a^2-b^2
so. {x^2-(y+z)^2}
=x^2-y^2-z^2-2yz
Answered by
0
x^2-(y+z)^2}
=x^2-y^2-z^2-2yz is the answer
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