Question

how to solve x+yp²=(1+xy)p

Answer 1

x + yp^2 = p + pxy
yp^2 -pxy = p - x
yp (p - x ) = p - x
yp = p- x/ p - x =1
y =1/p

Answer 2

x+yp²=(1+xy)p

x + yp² = p + xyp

x - p = xyp- yp²

x - p = yp ( x - p )

yp = $\frac{(x -p)}{( x - p )}$ = 1

yp = 1

y = $\frac{1}{p}$

Ans :-  y = $\frac{1}{p}$