Math, asked by farheenajaffri8801, 4 months ago

how to solve (y+3)whole square is equals to​

Answers

Answered by jack4610
0

Answer:

y² + 9 + 6y

Step-by-step explanation:

(a+b)² = a² + b² + 2ab

likewise,

(y+3)² = y² + 9 + 6y

Answered by aliabidi09
1

Answer:

See the answer below

Step-by-step explanation:

 {(y + 3)}^{2}  =  {y}^{2}  +  {(3)}^{2}  + 2(y)(3)

 =  {y}^{2}  + 9 + 6y

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