Question

how to solve y=
$\sqrt{4tan {}^{3} } x$
please how to solve this class 11 questions trigonometry expression
​

Answer 1

Answer:

Given :-

When measured at 27°C, the volume of Oxygen gas was 400ml, what would be the new volume at 127°C at constant pressure

To Find :-

New Volume

Solution :-

We know that

0°C = 273.15° K

27°C = 273.15 + 27 = 299.15° K

127° C = 273.15 + 127 = 399.15° K

V/T = V'/T'

\sf\dfrac{400}{299.15} =\dfrac{V'}{399.15}

299.15

400

=

399.15

V

′

\sf\dfrac{80}{59.83} = \dfrac{V'}{399.15}

59.83

80

=

399.15

V

′

\sf\dfrac{80}{59.83}\times \dfrac{399.15}{1} = V'

59.83

80

×

1

399.15

=V

′

\sf\dfrac{31932}{59.83} = V'

59.83

31932

=V

′

'\sf 533.72\; ml = V'533.72ml=V

′