How to solved after that I confused in last line plzzz solved
Our answer is 2asin*/2
Attachments:
chaudharyritika:
send the actual question
Answers
Answered by
1
To solve this question you can take help of Photomath app
Answered by
1
hi , as we know that ( formula )
cos 2A = 2sin^2 A - 1
then , what will be the value of cosA ?
cos A = 2 sin^2 A / 2 - 1
now what will be the value of
( 1 + cosA ) ?
CosA + 1 = 2sin^2 A /2
or
1 + cosA = 2sin^2 A / 2
now come to your problem ,
a √{ 2 ( 1 + cos A )
= a √( 2 ( 2 sin^2 A /2 ) )
= a √ ( 4 sin^2 A / 2 )
= a × √4 × √ sin^2 A / 2
= a × 2 × sin A /2
= 2a sin A / 2
hence , your answer = 2asinA /2
cos 2A = 2sin^2 A - 1
then , what will be the value of cosA ?
cos A = 2 sin^2 A / 2 - 1
now what will be the value of
( 1 + cosA ) ?
CosA + 1 = 2sin^2 A /2
or
1 + cosA = 2sin^2 A / 2
now come to your problem ,
a √{ 2 ( 1 + cos A )
= a √( 2 ( 2 sin^2 A /2 ) )
= a √ ( 4 sin^2 A / 2 )
= a × √4 × √ sin^2 A / 2
= a × 2 × sin A /2
= 2a sin A / 2
hence , your answer = 2asinA /2
Similar questions