How to sort Java array elements in ascending order?
Answers
import java.util.Scanner;
public class Ascending _Order
{
public static void main(String[] args)
{
int n, temp;
Scanner s = new Scanner(System.in);
System.out.print("Enter no. of elements you want in array:");
n = s.nextInt();
int a[] = new int[n];
System.out.println("Enter all the elements:");
for (int i = 0; i < n; i++)
{
a[i] = s.nextInt();
}
for (int i = 0; i < n; i++)
{
for (int j = i + 1; j < n; j++)
{
if (a[i] > a[j])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print("Ascending Order:");
for (int i = 0; i < n - 1; i++)
{
System.out.print(a[i] + ",");
}
System.out.print(a[n - 1]);
}
}
Output:
$ javac Ascending _Order.java
$ java Ascending _Order
Enter no. of elements you want in array:5
Enter all the elements:
4
3
2
6
1
Ascending Order:1,2,3,4,6
A program in Java to demonstrate sorting an Array in Ascending order -
import java.util.Arrays;
public class Sorting {
public static void main(String[ ] args) {
int[ ] array = {10, 3, 1, 6, 4, 8, 7, 2, 5, 9};
// Sorting in ascending order.
Arrays.sort(array);
// Printing the sorted array.
System.out.println(Arrays.toString(array));
}
}