Math, asked by abhishekdevyash, 1 day ago

how to take out perimeter of triangleFind the perimeter of the given triangle: 4a-3b,5a+4b,-a+2b​

Answers

Answered by samalswaraj11
0

Given-

Sides of the triangle 4a-3b,5a+4b,-a+2b

To find-

the perimeter of the given triangle.

Solution- Let the sides of the triangle be

A= 4a-3b

B=5a+4b

& C= -a+2b​

∴ the perimeter of the given triangle= Sum of all 3 sides of the triangle =A+B+C

=(4a-3b)+(5a+4b)+(-a+2b)

=4a-3b+5a+4b-a+2b

=8a-3b

Hence perimeter of the given triangle is 8a-3b.

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