Music, asked by jinnushourya16, 8 months ago

how to take x values in grap in polynomial

Answers

Answered by RajSrivastava1
0

Answer:

Take +x at right side of 0.

And

Take -x at left side of 0.

Answered by Anonymous
0

Answer:

o find the xxx-intercepts, we can solve the equation f(x)=0f(x)=0f, left parenthesis, x, right parenthesis, equals, 0.

\begin{aligned} f(x)&=(3x-2)(x+2)^2 \\\\ \tealD 0&= (3x-2)(x+2)^2\\ \\ \end{aligned}  

f(x)

0

​  

 

=(3x−2)(x+2)  

2

 

=(3x−2)(x+2)  

2

 

​  

 

\begin{aligned}&\swarrow&\searrow\\\\ 3x-2&=0&\text{or}\quad x+2&=0&\small{\gray{\text{Zero product property}}}\\\\ x&=\dfrac{2}{3}&\text{or}\qquad x&=-2\end{aligned}  

3x−2

x

​  

 

=0

=  

3

2

​  

 

​  

 

orx+2

orx

​  

 

=0

=−2

​  

 

Zero product property

​  

 

The xxx-intercepts of the graph of y=f(x)y=f(x)y, equals, f, left parenthesis, x, right parenthesis are \left(\dfrac23,0\right)(  

3

2

​  

,0)left parenthesis, start fraction, 2, divided by, 3, end fraction, comma, 0, right parenthesis and (-2,0)(−2,0)left parenthesis, minus, 2, comma, 0, right parenthesis.

Our work also shows that \dfrac 23  

3

2

​  

start fraction, 2, divided by, 3, end fraction is a zero of multiplicity 111 and -2−2minus, 2 is a zero of multiplicity 222. This means that the graph will cross the xxx-axis at \left (\dfrac 23, 0\right)(  

3

2

​  

,0)left parenthesis, start fraction, 2, divided by, 3, end fraction, comma, 0, right parenthesis and touch the xxx-axis at (-2,0)(−2,0)left parenthesis, minus, 2, comma, 0, right parenthesis.

Explanation:

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