Question

How to write 2.93 where 93 bar in p by q form where p and q are integers and q is not equal to 0

Answer 1

Heya !!

Here's your answer.. ⬇⬇

Let x = 2.93 ( bar on 93 )

x = 2.9393.. -----( 1 )

100x = 293.9393... ---( 2 )

Now, Subtract eq. ( 1 ) from eq. ( 2 )..

100x = 293.9393..
- x = 2. 9393..
----------------------------
99x = 291.00

x = 291/99

HOPE IT HELPS..

THANKS ^-^

Answer 2

Let x = 2.93 bar
_____________

As there are 2 numbers under bar, multiply 100

100×x = 100× 2.93 bar

100x = 293.93 bar
-x = -2.93 bar [subtract x]
______________
99x = 291 [bar cancelled]
______________


x = 291/99

x = 97/33


Now,

2.93 bar can be written as 97/33



I hope this will help you


-by ABHAY