Question

How to write a chemical equation and balance it? Explain it with example of H2S + O2= ?​

Answer 1

Answer:

H2S + O2 → H2O + SO2

Number of each atom on the reactant side: H is 2; S is 1; O is 2

Number of each atom on the product side: H is 2; S is 1; O is 3

Therefore, oxygen is out of balance. The common factor for 2 and 3 is 6, hence make oxygen 6 on the reactant side with a coefficient of 3 means the other atoms are out of balance as shown below:

H2S + 3O2 → H2O + SO2

Reactant side: H is 2; S is 1; O is 6

Product side: H is 2; S is 1; O is 3

To start with, you can place a coefficient of 2 in front of H2O to balance out the oxygen, giving:

H2S + 3O2 → 2H2O + SO2

Reactant side: H is 2; S is 1; O is 6

Product side: H is 4; S is 1; O is 4

Hydrogen is now out of balance, so a coefficient of 2 can be placed in front of H2S to give:

2H2S + 3O2 → 2H2O + SO2

Reactant side: H is 4; S is 2; O is 6

Product side: H is 4; S is 1; O is 4

Sulphur is still out of balance, so a coefficient of 2 can be placed in front of SO2 to give:

2H2S + 3O2 → 2H2O + 2SO2

Reactant side: H is 4; S is 2; O is 6

Product side: H is 4; S is 2; O is 6

I hope that helps