how to write a program in c++ finde the area of cub?
Answers
Answer:
using namespace std
int side;
cout<<"Enter the side of cube :";
cin>>side;
cout<<"Area of cube is "<<side*side<<"sq.m";
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Answer:
Example
Input-: side=3
Output-: volume of cube is: 27
Total surface area of cube is 54
Algorithm
Start
Step 1 -> declare function to find volume of cube
double volume(double a)
return (a*a*a)
Step 2 -> declare function to find area of cube
double volume(double a)
return (6*a*a)
Step 3 -> In main()
Declare variable double a=3
Print volume(a)
Print area(a)
Stop
CODE
#include <bits/stdc++.h>
using namespace std;
// function for volume of cube
double volume(double a){
return (a * a * a);
}
//function for surface area of cube
double area(double a){
return (6 * a * a);
}
int main(){
double a = 3;
cout<< "volume of cube is: "<<volume(a)<<endl;
cout<< "Total surface area of cube is "<<area(a);
return 0;
}
Output
volume of cube is: 27
Total surface area of cube is 54