Question

How to write application letter to hospital for name and address correction in hospital case paper

Answer 1

Answer:

Therefore

\purple{\sf \dag Acceleration = 2.5 m \: s^{-2} \dag }†Acceleration=2.5ms

−2

†

\purple {\sf \dag Distance \: Travelled = 5 \: m \dag }†DistanceTravelled=5m†

━━━━━━━━━━━━━━━━━━━━

Explanation:

Therefore

\purple{\sf \dag Acceleration = 2.5 m \: s^{-2} \dag }†Acceleration=2.5ms

−2

†

\purple {\sf \dag Distance \: Travelled = 5 \: m \dag }†DistanceTravelled=5m†

━━━━━━━━━━━━━━━━━Therefore

\purple{\sf \dag Acceleration = 2.5 m \: s^{-2} \dag }†Acceleration=2.5ms

−2

†

\purple {\sf \dag Distance \: Travelled = 5 \: m \dag }†DistanceTravelled=5m†

Therefore

\purple{\sf \dag Acceleration = 2.5 m \: s^{-2} \dag }†Acceleration=2.5ms

−2

†

\purple {\sf \dag Distance \: Travelled = 5 \: m \dag }†DistanceTravelled=5m†

Therefore

\purple{\sf \dag Acceleration = 2.5 m \: s^{-2} \dag }†Acceleration=2.5ms

−2

†

\purple {\sf \dag Distance \: Travelled = 5 \: m \dag }†DistanceTravelled=5m†

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