Question

how to write general solution for 2 sin squared x+sin squared 2x=2

Answer 1

2sin²x + sin²2x = 2
[ sin2x = 2sinx.cosx use this here ]

2sin²x + (2sinx.cosx)² = 2
2sin²x + 4sin²x.cos²x = 2
sin²x + sin²( 1 - sin²x) = 1
sin²x + sin²x - sin⁴x = 1
sin⁴x -2sin²x +1 = 0
(sin²x -1)² = 0
sin²x = 1 = sin²π/2
x = nπ ± π/2 where n is an integer

Answer 2

here is the answer

please mark as brainlist