how to write o.1692bar in p/q form
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Answered by
2
Answer:
answer is
1000x=1629.1629
x=0.1629
1000x-x=1629.1629-0.1629
x=1629by999
Answered by
1
Answer:
let x= o.1692 bar [equation 1 ]
multiplying equation one by 100
100x= 1692.1692 bar [equation 2 ]
subtracting equation 1 from 2
99x=1692
x=1692/99
therefore p/q form = 1692/99
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