Question

how to write sin 2 thetha in terms of sin square thetha

Answer 1

Step-by-step explanation:

WE KNOW THAT SIN 3X=3SINX - 4SIN^3X

HERE WE CAN TAKE 3X=2THETA

SO SIN(2THETA)=3SIN((2/3)THETA) - 4SIN^3 ((2/3)THETA)

= SIN((2/3)THETA) [ 3-4SIN^2((2/3)THETA) ]

Answer 2

Hey mate ☺️

✌️$\huge \red {Gud \: morning }$✌️

First, notice that the formula for the sine of the half-angle involves not sine, but cosine of the full angle. So we must first find the value of cos(A). To do this we use the Pythagorean identity

sin²(A) + cos²(A) = 1.

Hope it helps ♥️