how to write the equation of circle passing through (3, -6)?????
Answers
Answered by
0
Answer:
Step-by-step explanation:
(x-a)(x-a)+(y-b)(y-b) = r.r
Where
a = 3, b. = -6
And. r = radius
Which not given in the question
So we will take it. Zero
Put the values in formula and find your answer
ZiaAzhar89:
without radius how circle can be formed it is impossible so your answer is wrong
Similar questions