How two enantiomers of the asymmetric Ketone or Aldehyde is formed in nucleophilic addition reaction?
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Step 1 is addition of a nucleophile to the electrophilic carbonyl carbon. This forms C–Nu and breaks C–O (π), resulting in a negatively charged oxygen. Step 2 is addition of an acid (“protonation”), which results in formation of the O–H bond.
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