India Languages, asked by nongkhlawailyn8, 5 months ago

How was robinson second order different from his first?

Answers

Answered by shashiprabha1681

Answer:

The first-order derivatives are good to select the stongest edges by (hysteresis-)thresholding the gradient magnitude. The zero-crossings of the second-order derivatives are good for localization of the edge.

Explanation:

I hope these will work for you

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