History, asked by yashika11152, 9 months ago

how was the awadh annexed to the british empire by this system?​

Answers

Answered by VaibhavPratapSingh35
0

Awadh is also known in British historical texts as Avadh or Oudh, is a region in the modern Indian state of Uttar Pradesh, which was before independence known as the United Provinces of Agra and Oudh. Awadh is bounded by the Ganges Doab to the southwest, Rohilkhand to the northwest, Nepal to the north, and Purvanchal to the east. Its inhabitants are referred to as Awadhis.

It was established as one of the twelve original subahs (top-level imperial provinces) under 16th-century Mughal emperor Akbar and became a hereditary tributary polity around 1722, with Faizabad as its initial capital and Saadat Ali Khan as its first Subadar Nawab and progenitor of a dynasty of Nawabs of Awadh (often styled Nawab Wazir al-Mamalik). The traditional capital of Awadh was Faizabad, but the capital was later moved to Lucknow, also the station of the British Resident, which now is the capital of Uttar Pradesh.

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Answered by dreamgirl30
0

Answer:

Answer:

Step-by-step explanation:

माना कि

y=\dfrac{\sin x + \cos x}{\sin x - \cos x}y=

sinx−cosx

sinx+cosx

\begin{gathered}\dfrac{dy}{dx} =\dfrac{(sinx-cosx)\dfrac{d}{dx} (sinx+cosx)-(sinx+cosx)\dfrac{d}{dx}(sinx-cosx)}{(sinx-cosx)^2}\\ \\=\dfrac{(sinx-cosx)(cosx-sinx)-(sinx+cosx)(cosx+sinx)}{(sinx-cosx)^2}\\\\=\dfrac{-(cosx-sinx)^2-(sinx+cosx)^2}{(sinx-cosx)^2}\\\\=\dfrac{-(cos^2x+sin^2x-2cosxsinx)-(cos^2x+sin^2x+2sinxcosx)}{(sinx-cosx)^2}\\\\=\dfrac{-(1-2sinxcosx)-(1+2sinxcosx)}{(sinx-cosx)^2}\\\\=\dfrac{-1+2sinxcosx-1-2sinxcosx}{(sinx-cosx)^2}\\\\=\dfrac{-2}{(sinx-cosx)^2}\end{gathered}

dx

dy

=

(sinx−cosx)

2

(sinx−cosx)

dx

d

(sinx+cosx)−(sinx+cosx)

dx

d

(sinx−cosx)

=

(sinx−cosx)

2

(sinx−cosx)(cosx−sinx)−(sinx+cosx)(cosx+sinx)

=

(sinx−cosx)

2

−(cosx−sinx)

2

−(sinx+cosx)

2

=

(sinx−cosx)

2

−(cos

2

x+sin

2

x−2cosxsinx)−(cos

2

x+sin

2

x+2sinxcosx)

=

(sinx−cosx)

2

−(1−2sinxcosx)−(1+2sinxcosx)

=

(sinx−cosx)

2

−1+2sinxcosx−1−2sinxcosx

=

(sinx−cosx)

2

−2

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