how we Be the the HCF of x³ y²,x²y³
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Given,
Two angles =650,650
And the other two angles are equal.
Let the other angles be x,x.
Concept used:
The sum of the angles of a quadrilateral is given
=3600
Apply the above concept, we get
650+650+x0+x0=3600
130x0+2x0=3600
2x0=3600−1300
2x0=2300
x0=1150
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