Question

how we calculate the molecular mass of (NH)2SO4​

Answer 1

Answer:

$Molecular \: mass \: of \: (NH_4)_2 \: SO_4 \: (NH </p><p>4</p><p> </p><p> )</p><p>2</p><p> </p><p> SO </p><p>4$

Explanation:

The sum of masses of all atoms present in the compound is called as molecular mass.

In order to calculate the molecular mass of any substance, individual mass of atoms involved in the formation of compound must be calculated.

Accordingly to calculate the molecular mass of

$(NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

, the mass of each atom must be calculated in the following way:

In

$(NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

, 2 atoms of nitrogen, 8 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen are present.

Thus the molecular mass of the substance can be calculated by the following equation:

Molecular mass of (

$NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

= 2 (Atomic mass of nitrogen) + 8 (Atomic mass of hydrogen) + 1 (Atomic mass of Sulphur) + 4 (Atomic mass of oxygen)

Molecular mass of

$(NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

= (2×14.01) + (8×1.008) + (1×32.06) + (4×16.00)

Molecular mass of

$(NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

= 28.02+8.064+32.06+64.00

Molecular mass of

$(NH_4)_2SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2</p><p> </p><p> SO </p><p>4$

= 132.14u

Thus the Molecular mass of (

$NH_4)_2 SO_4(NH </p><p>4</p><p> </p><p> ) </p><p>2 </p><p> </p><p> \: SO \: </p><p>4</p><p>$

is calculated as

$132.14u.$