Question

how we can solve pythagorus triplets​

Answer 1

Answer:

If the number is odd: Square the number N and then divide it by 2. Take the integer that is immediately before and after that number i.e. (N2/2 -0.5) and (N2/2 +0.5).

Pythagorean triplet= N, (N2/2 -0.5), (N2/2 +0.5)

Example: Take number N=3.

On squaring the number, we get 9.

Now take the half of it. 9/2= 4.5

The integer immediately before 4.5= 4; the integer immediately after 4.5= 5

Therefore, the triplet is 3, 4, 5.

If the number is even: Take the half of that number N and then square it.

Pythagorean triplet= N, (N/2)2-1, (N/2)2+1

Example: Take number N=8

Half of N=4.

Pythagorean triplet= 8, (42-1), (42+1) i.e. 8, 15, 17

Note: If a, b, c is a Pythagorean triplet, then ka, kb, kc will also form a Pythagorean triplet; where k= integer. As (3, 4, 5) is a triplet, (6,8,10), (9,12,15),(12,16,20),...(30,40,50), all these will also be triplets.

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Answer 2

Answer:

Pythagorean triplet :

in a triplet of natural number, if the square of theargedt number is equal to the sum of the square of the remaining two numbers then the triplet is called a Pythagorean triplet.

for example :

in a triplet :(11,60,61)

${11}^{2} = 121 \: \: \: \: {60 } ^{2} = 3600 \: \: \: {61}^{2} = 3721$

And 121+3600=3721

the square of the largest number is equal to the sum of the square of the other two number.

11,60,61 is a Pythagorean triplet.