Question

How we can solve this sum that the product of two numbers is 56. What the sum is added to the squares of their sum and we get 128.Find two numbers?

Answer 1

xy=56

x+y+x2+y2=128

(x+y)+(x+y)^2 - 2xy=128

lets assume x+y=k

k+k^2-2(56)=128, from xy=56

k^2 +k-240=0

k=15,-16

so k=15

x+y=15

xy=56

x=8,y=7

hope it is helpful

mark as brain list