Question

how we done that? When the mixture of iodine and salt is heated, then iodine sublimates and salt is left.

Answer 1

Answer and Explanation:

$\huge \text{\boxed{\boxed{\mathbb{SUBLIMATION}}}}$

$\implies$ Sublimation is defined as the process by which a solid substance directly changes into vapour or gaseous phase without going through the liquid phase or vice versa

$\implies$ Substances that undergoes sublimation are called as sublimable substances

$\implies$ Some examples of sublimable substances are camphor, naphthalene, iodine, ammonium chloride etc

$\boxed{Solid \ \ \overset{\longleftarrow}{\overset{sublimation}{\longrightarrow}} \ \ Gas}$

$\implies$ In the given mixture of salt and iodine, iodine is a sublimable solid substance

$\implies$ When the given mixture is heated, iodine sublimes and turns into iodine vapours

$\implies$ Salt or NaCl has strong ionic bonds which is hard to break and hence, have high boiling point

$\implies$ Thus, on heating the given mixture of iodine and salt

Iodine sublimes away as vapours but,

Salt remains as such

$\implies$ This can be used as a method of seperation