Question

how we find the six digit largest number which is exactly divisible by 3,8 and 4​

Answer 1

there are three conditions for finding such a number:

1) all the digits of that number should equal to a number which is divisible by 3

2) the last two digits of this number should equal to a number which is divisible by 4

3) the last three digits of that number should equal to a number which is divisible by 8

for example, if the last two digits are 40, so it is divisible by 4. then adding 2 to the hundredth place, 240 is divisible by 8, so the number will be divisible by 8. the sum of digits in 240 are divisible by 3, so adding three more digits before that like 999240, and 27+6=33 which is divisible by 3.

so the largest six digit number is 999240, where this number is divisible by 3, 8 and 4.

for verification, i found out by calculator:

999240/3= 333080

999240/8= 124905

999240/4= 249810

pls mark as brainliest!!!