how we should decide which formula to use in trigonometry and electricity chapter?
Answers
Answer:
Firstly you must ask yourself whether the triangle has a right angle. If it has, you must then ask if it has any other angles (or you are asked to find another angle), if you are you can use the standard trig formula of SOHCAHTOA, if it hasn't, then you can use Pythagoras' theorem c2=a2+b2
Explanation:
Answer:
Firstly you must ask yourself whether the triangle has a right angle. If it has, you must then ask if it has any other angles (or you are asked to find another angle), if you are you can use the standard trig formula of SOHCAHTOA, if it hasn't, then you can use Pythagoras' theorem c2=a2+b2.
lectricity is the flow of charge in a conductor from anode to cathode. Electricity has varied applications. It acts as a tool to provide power to electrical devices. We can say the flow of charge builds up the current, which we call Electricity. To understand how the Electricity is generated, we need to understand the various basic parameters related to it like the voltage, current, resistance, conductivity and the relation among them.
Electricity Formula Diagram
Some of the commonly used Electricity formulae are listed below.
Quantity Formulas Unit
Current I I = Q / t
Q = Charge
t = time taken
Amperes (A)
Voltage V V = E / Q
or
V = W / Q
E = Energy, W = Work done
Volts (V)
Resistance R R = ρl / A
ρ = Resistivity,
l = length,
A = Area
or,
R = V / I
Ohm (Ω)
Power P P = VI Watts (W)
Conductivity σ sigma = 1 / ρ Siemens per meter (S/m)
Electricity Formulas are applied in calculating the unknown electrical parameters from the known in electric circuits.
Solved Examples
Example 1
An electric heater has a potential difference of 220 V and resistance is 70 Ω. Determine the magnitude of the current flowing through it.
Solution:
Given:
Resistance R = 70 Ω
Voltage V = 220 V
The current formula is given by
I = V / R
= 220 / 70
I = 3.1428 A
Example 2
An electrical lamp lights for 4 hours and draws a current of 0.5 A. Calculate the amount of charge flowing through the lamp.
Solution:
Current I = 0.5 A
Time taken t = 4 hours
t= 4 × 3600 = 14400 s,
Charge Q = I × t
= 0.5 ×14400
Q= 7200 C
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