Question

how we solve this problem​

Answer 1

GIVEN :

• $\tt m_1 \: = \: 1g \: and \: m_2 \: = \: 9g \: having \: equal \: in \: KE.$

Here,

$\tt m_1 \: = \: 1g$

$\tt m_2 \: = \: 9g$

$\tt KE \: = \: Kienatic \: energy$

TO FIND :

• Ratio of their momentum (p) = ?

FORMULA :

• $\tt P = \dfrac{\sqrt{2m_1(kE_1)}}{\sqrt{2m_2(kE_2)}}$

SOLUTION :

Here,

$\tt{ P_1 = {\sqrt{2m_1(KE_1)}}}$

$\tt{ P_2 = {\sqrt{2m_2(KE_2)}}}$

Now, we know that

$\tt \dfrac{P_1}{P_2} = \dfrac{\sqrt{2}\times\sqrt{m_1}\times\sqrt{kE_1}}{\sqrt{2}\times\sqrt{m_2}\times\sqrt{kE_2}}$

$\therefore$ $\sf KE_1 \: = \: KE_2$

$\tt \dfrac {p_1}{p_2} \: = \: \dfrac {\sqrt{m_1}}{\sqrt{m_2}}$

$\hookrightarrow \tt \dfrac {\sqrt{1}}{\sqrt{9}}$

$\hookrightarrow \tt \dfrac {1}{3}$

•°• Therefore, the ratio of their momentum is 1:3.