Physics, asked by khanbhai1650800, 11 months ago

how we solve this problem​

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Answered by Anonymous
5

GIVEN :

  • \tt m_1 \: = \: 1g \: and \: m_2 \: = \: 9g \: having \: equal \: in \: KE.

Here,

\tt m_1 \: = \: 1g

\tt m_2 \: = \: 9g

\tt KE \: = \: Kienatic \: energy

TO FIND :

  • Ratio of their momentum (p) = ?

FORMULA :

  • \tt P = \dfrac{\sqrt{2m_1(kE_1)}}{\sqrt{2m_2(kE_2)}}

SOLUTION :

Here,

\tt{ P_1 = {\sqrt{2m_1(KE_1)}}}

\tt{ P_2 = {\sqrt{2m_2(KE_2)}}}

Now, we know that

\tt \dfrac{P_1}{P_2} = \dfrac{\sqrt{2}\times\sqrt{m_1}\times\sqrt{kE_1}}{\sqrt{2}\times\sqrt{m_2}\times\sqrt{kE_2}}

\therefore \sf KE_1 \: = \: KE_2

\tt \dfrac {p_1}{p_2} \: = \: \dfrac {\sqrt{m_1}}{\sqrt{m_2}}

\hookrightarrow \tt \dfrac {\sqrt{1}}{\sqrt{9}}

\hookrightarrow \tt \dfrac {1}{3}

•°• Therefore, the ratio of their momentum is 1:3.

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