Question

how we solve |x+1|+|x-1| in term of function?

Answer 1

here,

f(X) = |X+1|+|X-1|

when X=1

f(X) = 2

when X=-1

f(X)=2

here, we have use the property of modulous....
that, if f(X)= |X+a| then the value of X comes out to be -a.



Therefore the required function is f(X)=2


Hope you get your answer.