how we will find the square root of 7 on the number line
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On the number line, draw a perpendicular line of length 1 unit from point (2,0).
Join the tip of the perpendicular line and origin. The line you got now has a length of
![\sqrt{ {2}^{2} + {1}^{2} } = \sqrt{5} \sqrt{ {2}^{2} + {1}^{2} } = \sqrt{5}](https://tex.z-dn.net/?f=+%5Csqrt%7B+%7B2%7D%5E%7B2%7D++%2B++%7B1%7D%5E%7B2%7D+%7D++%3D+++%5Csqrt%7B5%7D+)
Now project this length on the number line by drawing an arc using a compass.
Again draw unit perpendicular and repeat the procedures until you get
![\sqrt{ { \sqrt{5} }^{2} + {1}^{2} } = \sqrt{6} \\ \sqrt{ { \sqrt{6} }^{2} + {1}^{2} } = \sqrt{7} \sqrt{ { \sqrt{5} }^{2} + {1}^{2} } = \sqrt{6} \\ \sqrt{ { \sqrt{6} }^{2} + {1}^{2} } = \sqrt{7}](https://tex.z-dn.net/?f=+%5Csqrt%7B+%7B+%5Csqrt%7B5%7D+%7D%5E%7B2%7D+%2B++%7B1%7D%5E%7B2%7D++%7D++%3D++%5Csqrt%7B6%7D++%5C%5C++%5Csqrt%7B+%7B+%5Csqrt%7B6%7D+%7D%5E%7B2%7D++%2B++%7B1%7D%5E%7B2%7D+%7D++%3D++%5Csqrt%7B7%7D+)
Join the tip of the perpendicular line and origin. The line you got now has a length of
Now project this length on the number line by drawing an arc using a compass.
Again draw unit perpendicular and repeat the procedures until you get
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