how will be surface area of a cube change of its length of its edge halved and doubled.
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Answered by
9
it will be its four times
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29
If Halved :
T.S.A. = 6![a^{2}/2 a^{2}/2](https://tex.z-dn.net/?f=+a%5E%7B2%7D%2F2+)
=6
The area will be reduced 4 times
If doubled :
T.S.A. =6![2a^{2} 2a^{2}](https://tex.z-dn.net/?f=+2a%5E%7B2%7D)
=6![4a^{2} 4a^{2}](https://tex.z-dn.net/?f=+4a%5E%7B2%7D)
The area will be increased by 4 times
T.S.A. = 6
=6
The area will be reduced 4 times
If doubled :
T.S.A. =6
=6
The area will be increased by 4 times
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