Physics, asked by ammuchikkala525, 6 months ago

how will be the knetic energy of a body be affected if the velocity is increased three times

Answers

Answered by yashparab755
0

Answer:

A reference frame in three dimensional space is the coordinate frame X,Y,Z attached to each observer.

We use this frame to measure position of a body at any instant of time and if we make a plot of those positions at different times , we get a displacement -time curve or plot which helps us in finding many physical parameters/variables.

The slope of the curve gives us the velocity and if we square it and multiply with mass/2 then we get the kinetic energy of the body

K.E. = (1/2).mass. velocity^2

suppose there are different observers and they are moving with different velocities, then their measurements will get affected,

as for example we observe rain drops falling vertically with certain speed and when we start moving the rain drops appear to us slanting making an angle with the vertical. this is due to motion of the frame.

therefore in various frames of reference which are in relative motion the measurement of velocity will get affected and thus the kinetic energy measured by different observers will not be same.

another common example is -

suppose you are as an observer moving in a train with certain velocity and you observe another train moving on a parallel track and its moving very slowly as you observe…your measurements on its displacements with respect to time will give a lower speed , which is actually a relative speed with respect to the frame attached to you.

however , when we move to rest frame the train which appeared slowly moving past your bogie was moving with speed larger than your own speed.

Thus the kinetic energy depends on the observers frame of reference.

Answered by Job47lcc
0

Answer:

The Kinetic Energy increases 9 times.

Explanation:

As,

Kinetic Energy = mv^2 / 2.

If v' = 3v then,

Kinetic Energy' = mv'^2 /2.

Kinetic Energy ' = m (3v)^2 / 2.

Kinetic Energy' = 9mv^2 / 2.

Kinetic Energy' = 9 (mv^2/2).

Kinetic Energy' = 9 (Kinetic Energy)

It means that if the velocity is increased three times then the Kinetic Energy increases 9 times.

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