Math, asked by hadassahgrace29, 5 hours ago

how will i solve ₓ²₋5ₓ₋14 and what will be tha answer

Answers

Answered by MrMonarque
29

\Large{\underline{\underline{\red{\bold{Solution:}}}}}

 {x}^{2}  - 5x - 14 = 0 \\  {x}^{2} - 7x  + 2x - 14  = 0 \\ x(x - 7) + 2(x - 7) = 0 \\ (x - 7)(x + 2) = 0 \\ x = 7 \: (or) \:  - 2

  • \pink{\bold{x = 7\;\&\;-2}}

\Large{\tt{@MrMonarque}}

Hope It Helps You ✌️

Answered by kyra12389
1

Answer:

x²-5x-14

Step-by-step explanation:

x-7x+2x-14=0

x(x-7)+2(x-7)=0

(x-7)(x+2)=0

x=7 or x=-2

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