Question

how will resistance of a cylindrical conductor change if it is stretched so that it's length is doubled​

Answer 1

Answer:

Resistance will also get doubled

Explanation:

$resistance \: = \frac{ \gamma \: l }{a}$

$where \: \gamma \: is \: rho \: that \: is \: resistivity \: \\ l \: is \: length \: of \: the \: object \\ a \: is \: the \: area \: of \: the \: object$

So resistance is directly proportional to l (length)

Hence when the conductor is stretched, i.e, it's length 'l' becomes double, resistance will also become double