Question

How will the action of dilute hydro
chloric acid enable
you
ou to distinguish
between the following:
Sodium carbonate and sodium sulphite​

Answer 1

Explanation:

HEY MATE ..

(a). Sodium carbonate on treating with dil. HCl results in the formation of sodium chloride with the liberation of carbon dioxide gas.

Na2Co3 + 2HCL ➞ 2NaCl + H2O + Co2 .

Sodium sulphite on treating with dil. HCl results in the formation of sodium chloride with the liberation of sulphur dioxide gas.

Na2So3 + 2Hcl ➞2Nacl + H2O + So2.

(b). Sodium thiosulphate reacts with dil. HCl to produce sulphur dioxide gas and precipitates yellow sulphur. Sulphur is not precipitated when sulphites are treated with dil. HCl.

Na2S2O3 + 2HCL ➞2NaCl + H2O + So2 + S.

Sulphur is not precipitated when sulphites are treated with dil. HCl

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Answer 2

Answer:

Sodium carbonate on treating with dil. HCI results in the formation of sodium chloride with the liberation of carbon dioxide gas.

Reaction: Na2co3+2HCL----2Nacl+H2O+CO2.

Sodium sulphite on treating with dil. HCl results in the formation of sodium chloride with the liberation of sulphur dioxide gas.

Reaction: Na2so3+2HCL-----2Nacl+H2o+SO2.

Explanation:

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