Question

How will the distance of closest affected when the kinetic energy become double?

Answer 1

Answer:

r₀= closest approach to nucleus

Within this distance, K.E of the alpha particle is converted to potential energy.

Given, Z= 80, K.E= 8 MeV

K.E= (1/4πε₀){(Ze)(2e)/r₀}

r0= (1/4πε₀){(Ze)(2e)/K.E}

={9×10⁹×2×80×(1.6×10⁻¹⁹)²}/ (8×106×1.6×10⁻¹⁹)

= 2.88×10⁻¹⁴

As we know, r₀∝ (1/K.E)

So, if the distance of the closest approach is halved, Kinetic energy becomes doubled.

Answer 2

Answer:

How will the distance of closest affected when the kinetic energy become double?

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