Physics, asked by bhosale8851, 1 year ago

How will the energy stored in a capacitor change when the separation between the plates is doubled with a dielectric medium of dielectric constant 4 is introduced between the plates assuming the capacitor is disconnected from the dc source?

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Answered by subham322669
0

Explanation:

Step 1 of 4

(a)

When dielectric is inserted between the plates of an isolated capacitor, the charge remains the same. When capacitor is isolated, there is no way to go the charge. The capacitance increases as result of inserting the dielectric. The voltage across the capacitor decreases because the expression for the charge is as follows.

As charge remains the same, the capacitance increases, then the voltage across the capacitor must decreases.

In this case the energy decreases as the expression for the energy stored in a capacitor is as follows.

Chapter 17, Problem 16Q is solved.

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Corresponding Textbook

Physics (7th) edition 9780321625922 0321625927

Physics | 7th Edition

9780321625922ISBN-13: 0321625927ISBN: Douglas C GiancoliAuthors: Rent | Buy

Alternate ISBN: 9780321625915, 9780321869111, 9780321928931, 9780321929013, 9780321957177

Physics

(7th Edition)

Solutions for Chapter 17 Problem 16Q

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Problem 16Q: How does the energy stored in a capacitor change when a diel...

Solutions for Problems in Chapter 17 is solved

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