how will the magnetic field at the center of a circular coil carrying current change if the current through the coil is doubled and radius of the coil is half ?
Answers
Answer:
At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value.
Explanation:
The magnetic field at the centre of a circular coil carrying current is
B = mu(0) n I / (2r)
Where mu(0) is the permeability of free space, n is the number of turns in the coil, I the current in the coil and r it's radius.
It should be easy enough to get the answer you want.
Answer:
At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value.
Explanation:
Explanation:
The magnetic field at the centre of a circular coil carrying current is
B = mu(0) n I / (2r)
Where mu(0) is the permeability of free space, n is the number of turns in the coil, I the current in the coil and r it's radius.
It should be easy enough to get the answer you want.