Question

How will the pressure change when the area of contact is doubled?

Answer 1

Hello,
Here is your answer :
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Pressure refers to the force exerted by an object in per unit area.
So, pressure can be written as
$pressure = \frac{thrust}{area \: of \: contact}$
Where, thrust is the perpendicular force exerted by the object ( SI unis is Newton, denoted by 'N')
And, area of contact is the area where the force is applied(SI unit is square metres, denoted by m²)

Now,
If the area of the contact is doubled then pressure will be:
$pressure = \frac{thrust}{2 \times area} = \ \frac{1}{2} \times \frac{thrust}{area}$
So,
The pressure becomes 1/2 that is half of the previous one.
That implies that if the contact area is doubled then the pressure will make itself half.

BASIC CONCEPT :-
We know that pressure = thrust÷area
This means that pressure is inversely proportional to area of contact and directly proportional to the thrust(force applied on the contact area)

That is, if area increases pressure will decrease but if thrust increases the pressure will also increase.

Hope this will be helping you ✌️