Question

How will two equal discs, rotating with equal but opposite angular velocities and put on top of each other affect the spacetime “surrounding” them?

Answer 1

Now if we put two rotating identical discs (infinitely thin, but with a mass) on top of each other (somewhere in an empty region of intergalactic space and with their axes perpendicular to their surfaces aligned) and let them rotate contrary to one another with equal but opposite angular velocities (and zero friction) will this cause spacetime around them to be Euclidean again? In other words, will the curvatures of spacetime caused by the two discs "cancel each other out", resulting in a Euclidean geometry of spacetime "around" them? Or, on the contrary, will the curvature of spacetime increase? In other words, do the two curvatures of spacetime just "add up", because (maybe) there is no difference in the curvature of spacetime surrounding a disc if the direction of the angular velocity of a disc changes into the opposite direction?

I think I am right by saying that the space part of spacetime (in two dimensions) of one rotating disc looks like a cone with the tip of the cone at the center of the disc. Maybe the cones of the discs are oppositely directed (also in three dimensions where there are 3-d cones for this case).



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