How will we make 1 molar hcl solution from 35 stock solution?
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Answer:
To make 1 L of 1 mol/L HCl, you take 88 mL of the concentrated solution and add water to make a total of 1 L.
Explanation:
Assume that you want to prepare 1 L of 1 mol/L HCl.
Step 1. Calculate the moles of HCl needed.
Moles of HCl
=
1
L HCl
×
1 mol HCl
1
L HCl
=
1 mol HCl
Step 2. Calculate the mass of HCl Needed.
Mass of HCl
=
1
mol HCl
×
36.46 g HCl
1
mol HCl
=
36.46 g HCl
Step 3. Calculate the mass of solution required.
Mass of soln
=
36.46
g HCl
×
100 g soln
35
g HCl
=
104.2 g soln
Step 4. Calculate the volume of solution required.
Volume of soln
=
104.2
g soln
×
1 mL soln
1.18
g soln
=
88 mL soln
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