How will you connect 3 resistors each of 9 ohm so that equavalent resistor is
6 ohm
13.5 ohm
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1). Let us take two resistors in parallel while other in series along them
Therefore
1/ Rp = 1/ 9 + 1/9
= 2/9
Rp = 9/2 = 4.5 ohm
Now,
Rt = Rs + Rp
= 9 + 4.5
= 13.5 ohm
2). Let us take two resistors in series and one in parallel along them
Therefore
Rs = 9+9
= 18 ohm
1/Rt = 1/ Rs + 1/ Rp
= 1/ 18 + 1/ 9
= 1 + 2 / 18
= 3/18
Rt = 18/ 3
= 6 ohm
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